memalign()

Allocate aligned memory

Synopsis:

#include <malloc.h>

void *memalign( size_t alignment,
                size_t size );

Arguments:

alignment

The alignment that you want to use for the memory. This must be a multiple of size( void *).

size

The amount of memory you want to allocate, in bytes.

Library:

libc

Use the -l c option to qcc to link against this library. This library is usually included automatically.

Description:

The memalign() function allocates size bytes aligned on a boundary specified by alignment.

---

Because the malloc() implementation uses signed, 32-bit integers to represent the size internally, you can't allocate more than 2 GB in a single allocation. If the size is greater than 2 GB, memalign() indicates an error of ENOMEM.

---

Returns:

A pointer to the allocated block, or NULL if an error occurred (errno is set).

Errors:

EINVAL

The value of alignment isn't a multiple of size(void *).

ENOMEM

There's insufficient memory available with the requested alignment.

Classification:

QNX Neutrino

See also:

free(), malloc(), posix_memalign()