MALLOC(3) | Library Functions Manual | MALLOC(3) |
void *
malloc(size_t size);
void *
calloc(size_t number, size_t size);
void *
realloc(void *ptr, size_t size);
void
free(void *ptr);
The calloc() function allocates space for number objects, each size bytes in length. The result is identical to calling malloc() with an argument of “number * size”, with the exception that the allocated memory is explicitly initialized to zero bytes.
The realloc() function changes the size of the previously allocated memory referenced by ptr to size bytes. The contents of the memory are unchanged up to the lesser of the new and old sizes. If the new size is larger, the value of the newly allocated portion of the memory is undefined. Upon success, the memory referenced by ptr is freed and a pointer to the newly allocated memory is returned. Note that realloc() may move the memory allocation, resulting in a different return value than ptr. If ptr is NULL, the realloc() function behaves identically to malloc() for the specified size.
The free() function causes the allocated memory referenced by ptr to be made available for future allocations. If ptr is NULL, no action occurs.
The realloc() function returns a pointer, possibly identical to ptr, to the allocated memory if successful; otherwise a NULL pointer is returned, and errno is set to ENOMEM if the error was the result of an allocation failure. The realloc() function always leaves the original buffer intact when an error occurs.
The free() function returns no value.
if ((p = malloc(number * size)) == NULL) err(EXIT_FAILURE, "malloc");
The multiplication may lead to an integer overflow. To avoid this, calloc() is recommended.
If malloc() must be used, be sure to test for overflow:
if (size && number > SIZE_MAX / size) { errno = EOVERFLOW; err(EXIT_FAILURE, "allocation"); }
When using realloc(), one must be careful to avoid the following idiom:
nsize += 50; if ((p = realloc(p, nsize)) == NULL) return NULL;
Do not adjust the variable describing how much memory has been allocated until it is known that the allocation has been successful. This can cause aberrant program behavior if the incorrect size value is used. In most cases, the above example will also leak memory. As stated earlier, a return value of NULL indicates that the old object still remains allocated. Better code looks like this:
newsize = size + 50; if ((p2 = realloc(p, newsize)) == NULL) { if (p != NULL) free(p); p = NULL; return NULL; } p = p2; size = newsize;
For the implementation details, see jemalloc(3).
May 3, 2010 | NetBSD 6.1 |